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.[Clinical and immunological aspects of bronchial asthma (author’s transl)].
The bronchial asthma, is a chronic disease of the airways. Symptoms include wheezing, coughing, shortness of breath, tightness in the chest, and generalized itching. There are three stages of bronchial asthma: acute stage, subacute stage, and chronic stage. The most common cause of bronchial asthma is a hypersensitivity reaction of the airways in response to certain environmental conditions or chemicals. The treatment of bronchial asthma is directed to control the symptoms and to alleviate the complications. Aspirin, anticholinergics, beta 2-adrenergic agonists, topical corticosteroid, and theophylline are the most commonly used drugs in the treatment of asthma. Theophylline is usually effective in the initial management of asthma.Q:
Applying intervals: Pythagorean triple
Define $\quad a \leq b \leq c, \quad 0 \leq a,b,c \quad $.
Prove that :
$\quad \frac{a^2+b^2}{c} \quad $ is a Pythagorean triple
Hint: Use the fact that $\quad \frac{a^2+b^2}{a+b} \quad $ is a Pythagorean triple
MY ATTEMPT:
I want to use that hint to prove that the number in the title is a triple.
Hence I assume :
$\quad \frac{a^2+b^2}{c}=\frac{a^2+b^2}{a+b}$
I also know that :
$\quad \frac{a^2+b^2}{a+b}=(a-b)(a+b)$
I get $\quad (a-b)(a+b)=c$
But this is as far as I can go, how can I get $(a-b)(a+b)=c$?
A:
Note that $a\leq b\leq c$
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